.08x-1.2x^2=0

Solution for .08x-1.2x^2=0 equation:

.08x-1.2x^2=0

a = -1.2; b = .08; c = 0;
Δ = b2-4ac
Δ = .082-4·(-1.2)·0
Δ = 0.0064
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(.08)-\sqrt{0.0064}}{2*-1.2}=\frac{-0.08-\sqrt{0.0064}}{-2.4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(.08)+\sqrt{0.0064}}{2*-1.2}=\frac{-0.08+\sqrt{0.0064}}{-2.4}
$